Day 70: Implementing shimari and kakari

This is the way I programmed what I showed in the last posts about shimari and kakari:

public int keimaShimariKakari(int move,Board board,int color){ int n=board.getBoardSize(); boolean fivethree=false; int points=0; ArrayList<integer> positions=new ArrayList<>(); ArrayList<integer> komoku=new ArrayList<>(); //103-64 in 19x19 positions.add((n+1)*5+3); komoku.add((n+1)*3+4); //65-83 positions.add((n+1)*3+5); komoku.add((n+1)*4+3); //117-76 positions.add((n+1)*6-4); komoku.add((n+1)*4-4); //74-97 positions.add((n+1)*4-6); komoku.add((n+1)*5-3); for(int i=0;i<positions.size();i++){ fivethree=oneDependsOnAnother(move,positions.get(i),komoku.get(i),board); if(fivethree==true){ if(board.getMove(move)==color){ points=WeightValues.keimashimari; }else{ points=WeightValues.keimakakari; } break; } } return points; }

What is oneDependsOnAnother? Well... it is to see if the move is in a position and to make something it depends on another move. For example, to make this shimari you need first a komoku. If there is that komoku move and the move is in the 3-5 then return true. Let's see this in code:

public boolean oneDependsOnAnother(int move,int moveEvaluated, int moveDepend, Board board){
        boolean isGood=false;
        if(move==moveEvaluated && board.getMove(moveDepend)!=0){
            isGood=true;
        }
        return isGood;
    }

I can do the same now with other combinations, methods should be similar.